How does higher-order QAM affect bandwidth efficiency and required Eb/N0 for the same BER?

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Multiple Choice

How does higher-order QAM affect bandwidth efficiency and required Eb/N0 for the same BER?

Explanation:
Higher-order QAM increases bandwidth efficiency by packing more bits into each symbol. Since each symbol now conveys log2(M) bits, using a higher M with the same symbol rate boosts the data rate and makes better use of the available bandwidth. But the constellation points become closer together in the signal space, so the system becomes more sensitive to noise. To achieve the same error rate (BER), you must raise the energy per bit relative to the noise, i.e., increase Eb/N0. So, higher-order QAM provides higher spectral (bandwidth) efficiency, but requires a higher Eb/N0 to maintain the same BER.

Higher-order QAM increases bandwidth efficiency by packing more bits into each symbol. Since each symbol now conveys log2(M) bits, using a higher M with the same symbol rate boosts the data rate and makes better use of the available bandwidth. But the constellation points become closer together in the signal space, so the system becomes more sensitive to noise. To achieve the same error rate (BER), you must raise the energy per bit relative to the noise, i.e., increase Eb/N0. So, higher-order QAM provides higher spectral (bandwidth) efficiency, but requires a higher Eb/N0 to maintain the same BER.

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