In the Shannon-Hartley theorem, if you increase the bandwidth while keeping SNR constant, how does the channel capacity change?

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Multiple Choice

In the Shannon-Hartley theorem, if you increase the bandwidth while keeping SNR constant, how does the channel capacity change?

Explanation:
The key idea here is how channel capacity depends on bandwidth when the signal-to-noise ratio is held constant. In the Shannon-Hartley formula, capacity equals bandwidth times the logarithm term log2(1 + SNR). If SNR stays the same, that logarithmic factor is constant, so the only changing variable is bandwidth. Therefore, capacity scales directly with bandwidth: doubling the bandwidth doubles the capacity, because C = B × [constant]. This makes sense because wider bandwidth allows more independent signal dimensions per second to carry information, assuming the same SNR.

The key idea here is how channel capacity depends on bandwidth when the signal-to-noise ratio is held constant. In the Shannon-Hartley formula, capacity equals bandwidth times the logarithm term log2(1 + SNR). If SNR stays the same, that logarithmic factor is constant, so the only changing variable is bandwidth. Therefore, capacity scales directly with bandwidth: doubling the bandwidth doubles the capacity, because C = B × [constant]. This makes sense because wider bandwidth allows more independent signal dimensions per second to carry information, assuming the same SNR.

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